What is the minimum number of unique test cases required for a decision table where one condition has two equivalence partitions?

In a decision table, conditions and actions are mapped to determine all possible scenarios for testing a system. When considering a condition with two equivalence partitions, each partition represents a distinct scenario that must be evaluated. Since there are two equivalence partitions for one condition, there are two possible states that this condition can take.

For a decision table, the minimum number of unique test cases required is typically calculated by examining both conditions and their corresponding partitions or states. If there is only one condition with two distinct partitions, you would need to create at least one test case for each partition, resulting in two.

However, the answer suggests that four unique test cases are required, indicating that there may be additional factors or conditions influencing this need. This typically occurs in contexts where other conditions or actions must be considered in conjunction with the original condition.

If other conditions exist, the combinations of these conditions with the original condition would lead to an increase in the number of required test cases. For example, if there were two conditions with two states each, the minimum number of unique combinations would typically be calculated as ( 2 \times 2 = 4 ).

Therefore, considering the context of decision tables and the implications of mutual conditions, four unique test cases